120
풀이
입력받은 배열 내 최댓값을 찾고 주어진 식대로 계산하여 출력하면 됩니다.
코드
C
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 | #include <stdio.h>int main () { int n, i; double all = 0, max = 0; double score[1000]; scanf("%d", &n); for(i = 0; i < n; i++){ scanf("%lf", &score[i]); if(max < score[i]){ max = score[i]; } } for(i = 0; i < n; i++){ all += score[i]/max*100; } printf("%lf", all/(double)n); return 0;} |
C++
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 | #include <iostream>using namespace std;int main () { int n; double all = 0, max = 0; double score[1000]; cin>>n; for(int i = 0; i < n; i++){ cin>>score[i]; if(max < score[i]){ max = score[i]; } } for(int i = 0; i < n; i++){ all += score[i]/max*100; } cout<<all/(double)n; return 0;} |
Java
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 | import java.util.Scanner;public class Main { public static void main(String[] args) { Scanner sc = new Scanner(System.in); double all = 0, max = 0; int n = sc.nextInt(); double score[] = new double[n]; for(int i = 0; i < n; i++){ score[i] = sc.nextInt(); if(max < score[i]){ max = score[i]; } } for(int i = 0; i < n; i++){ all += score[i]/max*100; } System.out.println(all/(double)n); }} |
Python
1 2 3 4 5 6 7 8 9 | n = int(input())score = list(map(int, input().split()))max = max(score)all = 0for s in score: all += s/max*100;print(all/n) |
문제 출처
https://www.acmicpc.net/problem/1546